Sample

8.48 A seek of 20 pages was taken without replacement from the 1,591-page face pack directory Ameritech Pages Plus Yellow Pages. On each page, the mean athletic field of a function devoted to vaunt ads was measured (a display ad is a large block of multicolored illustrations, maps, and text). The data (in squ are millimeters) are shown below: 0 260 356 403 536 0 268 369 428 536 268 396 469 536 162 338 403 536 536 cxxx (a) Construct a 95 percent agency breakup for the true mean. (b) Why ability normality be an slue here? (c) What ideal surface would be needed to mystify an error of }10 unbowed millimeters with 99 percent confidence? (d) If this is non a intelligent requirement, suggest one that is. (Data are from a project by MBA student Daniel R. Dalach.) DisplayAds A: n=20, meanspirited x=346.5, old-hat deviation s=170.38 Since n<30, we must use t-table: d.f =19 For 95% confidence ?=0.05, a/2=0.025 From t-table at d.f=19=2.

093 office time interval=346.5 2.903×(170.38/20)=346.5 79.74= (266.76, 426.24) Confidence interval is (266.76, 426.24) B: Normality whitethorn be an issue because the sample of 20 may not have been selected from the population in a random manner. C: Standard deviation=170.38 E=10=99%, Z=2.576 Sample size n=ZE2 D: 99% confidence may be to a fault high for a dissemination that may not be normal. Dropping the confidence may reduce the required sample size.If you want to get a full essay, order it on our website: OrderEssay.net

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